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Question:
How `k_(2)(cr_(2)O7 is prepared? Give the oxidizing reation of the former
Answer:

1) Preparation of K2Cr2O7

Dichromates are generally prepared from chromate, which in turn are obtained by the fusion of chromite ore (FeCr2O4 ) with sodium or potassium carbonate in free access of air. The reaction with sodium carbonate occurs as follows:

4 FeCr2O4 + 8 Na2CO3 + 7 O2 → 8 Na2CrO4 + 2 Fe2O3 + 8 CO2

The yellow solution of sodium chromate is filtered and acidified with sulphuric acid to give a solution from which orange sodium dichromate, Na2Cr2O7.2H2O can be crystallised.

2Na2CrO4 + 2H+ → Na2Cr2O7 + 2Na+ + H2O

Sodium dichromate is more soluble than potassium dichromate. The latter is therefore, prepared by treating the solution of sodium dichromate with potassium chloride.

Na2Cr2O7 + 2KCl → K2Cr2O7 + 2NaCl

Orange crystals of potassium dichromate crystallise out.

 

2) Oxidising action of K2Cr2O7

In acidic solution, it acts as oxidising agent.

For e.g. It oxidises Fe2+ to Fe3+ 

Cr2O72– + 14 H+ + 6 Fe2+ → 2 Cr3+ + 6 Fe3+ + 7 H2O

 

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